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  1. Rajat

    MODERATE Examine this series: 6, 8, 20, 36, 76.

    For series, 6,8,20,36,72 6,(6*2-4=8),(8*2+4=20),(20*2-4=36),........ So for the next series, 20,(20*2-4=36),(36*2+4=76),(76*2-4=148),..... Ans. 148
  2. Rajat

    MODERATE Error of 10% Excess on Opposite Sides of Square and 10% Shortage on Other

    Let original area, A = x² ; side = x By counting error in it, Side AB = x + 0.1x = 1.1x Side BC = x - 0.1x = 0.9x So now, New area (say) Z = 1.1x*0.9x = 0.99x² So Error percent. = {(A -Z)/A}*100 = (1 - 0.99)*100 = 1% Ans
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