a total sum of ages of 5 membered family 3 years ago = 80
average age of each member let we consider as = 80/5= 16
present average age of family member is same...
sum of ages is 6 member (5+1 new baby)= 6*16= 96
80+5(3)= 95
therefore 6 th member i.e baby age is .. 96-95= 1 year
first man has to take goat with him then he leave that to other nearer bank where he has to go... then he has take cabbage to other side means where he has to go... then he carry wolf to the cabbage side then go back to the bank where he left the goat... then carry it and reach the other side...
x=73 and y=48
first i write down problem as u given then i calculate the diferences between the numbers for example duference between 8 and 14 is 6, then 14 and 19 is 5.... then i add the differences 5+6 to the 19 and i get 30.. then the difference between 19 and 30 is 11.. 11+previous number...